(1/2)10x^2+20x=480

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Solution for (1/2)10x^2+20x=480 equation: 



(1/2)10x^2+20x=480

We move all terms to the left:

(1/2)10x^2+20x-(480)=0



Domain of the equation: 2)10x^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)10x^2+20x-480=0

We add all the numbers together, and all the variables

20x+(+1/2)10x^2-480=0

We multiply all the terms by the denominator


20x*2)10x^2+(-480*2)10x^2+1=0

We add all the numbers together, and all the variables

20x*2)10x^2+(-960)10x^2+1=0

Wy multiply elements

40x^2-960)10x^2+1=0

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